故障描述:
+ A! A" n/ a- Z4 F退出登录时出现”您当前的访问请求当中含有非法字符,已经被系统拒绝“错误。
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解决方法:
- F& Q. I* D9 Z& ^打开 sourceclassdiscuzdiscuz_application.php 文件
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找到
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private function _xss_check() {
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static $check = array('"', '>', '<', ''', '(', ')', 'CONTENT-TRANSFER-ENCODING');
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. H$ X4 m5 ~: v2 m& Y) r if(isset($_GET['formhash']) && $_GET['formhash'] !== formhash()) {
; l6 j R# z* L2 A+ }# s system_error('request_tainting');
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! E% @; [/ b1 [) @ if($_SERVER['REQUEST_METHOD'] == 'GET' ) {
# V) p9 g8 X. {& O8 | $temp = $_SERVER['REQUEST_URI'];
2 J' q: m# K' l& @* `, | } elseif(empty ($_GET['formhash'])) {
" D X; M. Y8 ^' O: I $temp = $_SERVER['REQUEST_URI'].file_get_contents('php://input');
! Z. `% a7 P+ ]3 n+ ~% Z3 a } else {
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$temp = '';
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) [+ P& ]* d( V) G! X' m0 b5 G0 Y0 h* l O if(!empty($temp)) {
2 [' g# D5 v' E $temp = strtoupper(urldecode(urldecode($temp)));
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foreach ($check as $str) {
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if(strpos($temp, $str) !== false) {
) f+ \3 W( x. s- e1 ^3 \ system_error('request_tainting');
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* G% T* h2 z" u; k, o( F: v$ C1 z return true;
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}
2 B. h& W- v1 D) p3 t Q修改为
. l' w- d$ p0 Q* f' Uprivate function _xss_check() {
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$temp = strtoupper(urldecode(urldecode($_SERVER['REQUEST_URI'])));
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if(strpos($temp, '<') !== false || strpos($temp, '"') !== false || strpos($temp, 'CONTENT-TRANSFER-ENCODING') !== false) {
- R, \% { K3 K& H/ K0 B system_error('request_tainting');
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return true;
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